Get text from xPath

Question

How Can I find a value from example of using Xpath.

I need to get number of adults ?

http://www.easyjet.com/en/

<input id="Adults-257083" class="passenger-amount ng-pristine ng-valid ng-valid-pattern ng-valid-maxlength ng-valid-amount ng-touched" type="number" ej-prevent-non-numeric-keys="" ng-change="ResetIfNotANumber()" ng-model-options="{allowInvalid: true, updateOn: 'blur'}" ng-model="Passengers[Type]" ej-valid-on-invalid="ValidAmount(true)" ej-valid-key="amount" ej-valid="ValidAmount()" maxlength="2" inputmode="numeric" pattern="^\d*$" name="Adults" aria-invalid="false" style=""/>

Comments

your question is not clear yet. Are trying to automate? If so, what language and framework are you using? Kindly explain your problem in details.

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I need to get value from that webelement. I need to get number.

Answer 1

If you are using chrome, you can do right click > inspect element. Now you will see element highlited in inspect window. Here you can right click > copy and "copy xpath".

Here is your xPath

//*[@id="Adults-906830"]

Also, I see that your id is dynamic. So, you can try using regular expression.

//*[starts-with(@id,"Adults-\d+")]

Comments

Hi,

No I can't help with that :(
Look example :

Text of button:
Console.WriteLine(ObjectRepository.Driver.FindElement(By.XPath("//button[@class='ej-button rounded-corners arrow-button search-submit']")).Text);
Results: Show flights

Text(number) of adults:
Console.WriteLine(ObjectRepository.Driver.FindElement(By.XPath("//input[@id='Adults-926048']")).Text);
Results: Error

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Do you want to try.

Console.WriteLine(ObjectRepository.Driver.FindElement(By.XPath("//*[starts-with(@id,\"Adults-\d+\")]")).Text);

Let me know how it goes.

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Error    CS1009    Unrecognized escape sequence    SeleniumWebdriver
Error in char "d"

Answer 2

From console, just get the element using name

Webelement Adultnumber = Driver.FindElement(By.name('Adults")).getText;

u can access the number using "adultnumber"

where u can get the number for that webelement.

Using xpath =//*[@name="Adults"]